Factor. \[ w^{3}-64 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $w^{3}-64=\square$ B. $w^{3}-64$ is prime.

Step 1 ：The given expression is \(w^{3}-64\).

Step 2 ：This is a difference of cubes problem. The formula for factoring the difference of cubes is \(a^{3} - b^{3} = (a - b)(a^{2} + ab + b^{2})\).

Step 3 ：In this case, \(a = w\) and \(b = 4\) because \(4^{3} = 64\).

Step 4 ：We can use this formula to factor the expression.

Step 5 ：Applying the formula, we get \(w^{3}-64=(w-4)(w^{2}+4w+16)\).

Step 6 ：\(\boxed{w^{3}-64=(w-4)(w^{2}+4w+16)}\) is the final answer.