Problem
If the variation equation is given as \(y = kx^2\), and the point \((2,8)\) lies on the graph of this equation, what is the constant of variation \(k\)?
Solution
Step 1 ：Substitute the given point \((2,8)\) into the equation \(y = kx^2\), we get \(8 = k(2^2)\)
Step 2 ：Solving the equation for \(k\), we get \(k = \frac{8}{2^2} = \frac{8}{4} = 2\)
