Step 1 :Given the formula for the loudness level of a sound, $D=10\left(\log I-\log I_{0}\right)$, where $I$ is the intensity of the sound, in watts per meter ${ }^{2}$, and $\mathrm{I}_{0}$ is the intensity of a sound barely audible to the human ear.
Step 2 :Using the properties of logarithms, we can combine the two logarithms in the parentheses into a single logarithm by division. This is because the difference of two logarithms is equal to the logarithm of the quotient of their arguments.
Step 3 :So, we can rewrite the formula as $D=10\log \left(\frac{I}{I_{0}}\right)$.
Step 4 :\(\boxed{D=10\log \left(\frac{I}{I_{0}}\right)}\) is the final answer.