c. $n=35, \pi=.85$ (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) \begin{tabular}{|l|l|} \hline & \\ \hline Mean & \\ \hline Standard deviation & \\ \hline \end{tabular}

Step 1 ：The problem provides the parameters for a binomial distribution: n=35 and p=0.85.

Step 2 ：The mean of a binomial distribution is calculated using the formula \(\mu = np\). Substituting the given values, we get \(\mu = 35 \times 0.85 = 29.75\).

Step 3 ：The standard deviation of a binomial distribution is calculated using the formula \(\sigma = \sqrt{np(1-p)}\). Substituting the given values, we get \(\sigma = \sqrt{35 \times 0.85 \times (1-0.85)} = 2.112463017427761\).

Step 4 ：Rounding the standard deviation to four decimal places, we get \(\sigma = 2.1125\).

Step 5 ：Final Answer: The mean is \(\boxed{29.75}\) and the standard deviation is \(\boxed{2.1125}\).