Solve the system of equations by substitution. \[ \begin{array}{l} y=6 x-13 \\ 3 x+2 y=19 \end{array} \] The solution is $\square$. (Simplify your answer. Type an ordered pair.)

Step 1 ：Given the system of equations: \[\begin{array}{l} y=6 x-13 \\ 3 x+2 y=19 \end{array}\]

Step 2 ：Substitute the expression for y from the first equation into the second equation: \[3x + 2(6x - 13) = 19\]

Step 3 ：Simplify the equation to find the value of x: \[15x - 26 = 19\] which gives \[x = 3\]

Step 4 ：Substitute x = 3 back into the first equation to find the value of y: \[y = 6*3 - 13\] which gives \[y = 5\]

Step 5 ：Final Answer: The solution to the system of equations is \(\boxed{(3, 5)}\)