Step 1 :We are conducting a multinomial hypothesis test $(\alpha=0.05)$ for the claim that all 5 categories are equally likely to be selected. The observed and expected frequencies for each category are given in the table.
Step 2 :The chi-square test-statistic for this data is \(\chi^{2}=25.018\).
Step 3 :The degrees of freedom for this test is \(d.f. = 4\).
Step 4 :The p-value is the probability that a chi-square statistic would be as extreme as, or more extreme than, the observed statistic, given the null hypothesis.
Step 5 :Using the chi-square cumulative distribution function (CDF), we calculate the p-value.
Step 6 :Final Answer: The p-value for this sample is \(\boxed{4.989 \times 10^{-5}}\).