In the table below, the Solution 1 column gives one of the solutions of a quadratic equation. Fill in the Solution 2 column with the other solution of the quadratic equation. Important: Write your answer in the form $a+b i$ \begin{tabular}{|c|c|c|} \hline No. & Solution 1 & Solution 2 \\ \hline 1 & $1+4 i$ & \\ \hline 2 & $-12-i$ & \\ \hline 3 & $\frac{3}{2}-\frac{i}{2}$ & \\ \hline 4 & $-5 i+2$ & \\ \hline \end{tabular}

Step 1 ：To find the other solution of a quadratic equation, we can use the fact that if \(a+bi\) is a solution, then its conjugate \(a-bi\) is also a solution.

Step 2 ：For No. 1, the given solution is \(1+4i\). The other solution (Solution 2) will be the conjugate of this, which is \(1-4i\).

Step 3 ：For No. 2, the given solution is \(-12-i\). The other solution (Solution 2) will be the conjugate of this, which is \(-12+i\).

Step 4 ：For No. 3, the given solution is \(\frac{3}{2}-\frac{i}{2}\). The other solution (Solution 2) will be the conjugate of this, which is \(\frac{3}{2}+\frac{i}{2}\).

Step 5 ：For No. 4, the given solution is \(-5i+2\). The other solution (Solution 2) will be the conjugate of this, which is \(2+5i\).

Step 6 ：So the completed table with Solution 2 filled in is:

Step 7 ：\begin{tabular}{|c|c|c|} \hline No. & Solution 1 & Solution 2 \\ \hline 1 & \(1+4 i\) & \(1-4i\) \\ \hline 2 & \(-12-i\) & \(-12+i\) \\ \hline 3 & \(\frac{3}{2}-\frac{i}{2}\) & \(\frac{3}{2}+\frac{i}{2}\) \\ \hline 4 & \(-5 i+2\) & \(2+5i\) \\ \hline \end{tabular}

Step 8 ：\(\boxed{\text{The other solutions are } 1-4i, -12+i, \frac{3}{2}+\frac{i}{2}, 2+5i \text{ respectively for each given solution.}}\)