Step 1 :Given values are: sample mean (\(\bar{x}\)) = 6.3, population standard deviation (\(\sigma\)) = 1.2, sample size (n) = 271, and Z-score for 90% confidence level = 1.645.
Step 2 :First, calculate the margin of error using the formula: Margin of Error = Z-score * \(\sigma / \sqrt{n}\).
Step 3 :Substitute the given values into the formula: Margin of Error = 1.645 * (1.2 / \(\sqrt{271}\)) = 0.11991196032415735.
Step 4 :Next, calculate the confidence interval using the formula: Confidence Interval = \(\bar{x} \pm\) Margin of Error.
Step 5 :Substitute the values into the formula: Lower endpoint = 6.3 - 0.11991196032415735 = 6.2 (rounded to one decimal place), Upper endpoint = 6.3 + 0.11991196032415735 = 6.4 (rounded to one decimal place).
Step 6 :Final Answer: The 90% confidence interval for the mean number of computer games purchased each year is \(\boxed{[6.2, 6.4]}\).