Problem
For the given confidence level and values of $x$ and $n$, find the following. \[ x=44, n=99, \text { confidence tevel } 98 \% \] Part: $0 / 3$ Part 1 of 3 (a) Find the point estimate. Round the answers to at least four decimal places, if necessary. The point estimate for the given data is 0.4444 Part: $1 / 3$ Part 2 of 3 (b) Find the standard error. Round the answers to at least four decimal places, if necessary. The standard error for the given data is $\square$.
Solution
Step 1 ：Calculate the point estimate as the sample proportion, which is \(x/n\). Given that \(x=44\) and \(n=99\), the point estimate is \(44/99 = 0.4444\).
Step 2 ：Calculate the standard error (SE) of the sample proportion as \(\sqrt{p(1-p)/n}\), where \(p\) is the point estimate.
Step 3 ：Substitute the values into the formula to get the standard error as \(\sqrt{0.4444*(1-0.4444)/99} = 0.0500\).
Step 4 ：\(\boxed{0.0500}\) is the standard error for the given data.
