Find the ordered pair solutions for the function \(f(x) = 3x^2 - 2x + 1\) when \(x = -1, 0, 1\).

Step 1 ：First, substitute \(x = -1\) into the function: \(f(-1) = 3(-1)^2 - 2(-1) + 1 = 3 + 2 + 1 = 6\)

Step 2 ：Next, substitute \(x = 0\) into the function: \(f(0) = 3(0)^2 - 2(0) + 1 = 0 + 0 + 1 = 1\)

Step 3 ：Finally, substitute \(x = 1\) into the function: \(f(1) = 3(1)^2 - 2(1) + 1 = 3 - 2 + 1 = 2\)