The grade $\mathrm{x}$ of a hill is a measure of its steepness. For example, if a road rises 10 feet for every 100 feet of horizontal distance, then it has an uphill grac of $x=\frac{10}{100}$, or $10 \%$. The braking (or stopping) distance $D$ for a car traveling at $50 \mathrm{mph}$ on a wet, uphill grade is given by $D(x)=\frac{2500}{30(0.3+x)}$. Complete parts (a) through (c). (a) Evaluate $\mathrm{D}(0.01)$ and interpret the result. Select the correct answer below and, if necessary, fill in the answer box to complete your choice. A. $\mathrm{D}(0.01) \approx \square \mathrm{ft}$ and it represents the braking distance for a car traveling at $50 \mathrm{mph}$ on a wet $1 \%$ uphill grade. (Round to the nearest whole number as needed.) B. $D(0.01) \approx \square$ ft. and represents the braking distance for a car traveling at $50 \mathrm{mph}$ on a wet $0.01 \%$ uphill grade. (Round to the nearest whole number as needed.)

Step 1 ：The grade \(x\) of a hill is a measure of its steepness. For example, if a road rises 10 feet for every 100 feet of horizontal distance, then it has an uphill grade of \(x=\frac{10}{100}\), or 10%. The braking (or stopping) distance \(D\) for a car traveling at 50 mph on a wet, uphill grade is given by \(D(x)=\frac{2500}{30(0.3+x)}\).

Step 2 ：The question asks to evaluate the function D(x) at x=0.01. This function represents the braking distance for a car traveling at 50 mph on a wet, uphill grade. The value of x represents the grade of the hill, so in this case, the hill has a grade of 1% (since 0.01 is equivalent to 1%). Therefore, we need to substitute x=0.01 into the function and calculate the result.

Step 3 ：Substitute x=0.01 into the function: \(D(0.01) = \frac{2500}{30(0.3+0.01)}\).

Step 4 ：Calculate the result: \(D(0.01) = 268.81720430107526\).

Step 5 ：Round the result to the nearest whole number: \(D(0.01) \approx 269\) feet.

Step 6 ：The function D(0.01) evaluates to approximately 269 feet (rounded to the nearest whole number). This represents the braking distance for a car traveling at 50 mph on a wet 1% uphill grade. Therefore, the correct answer is \(\boxed{269}\) feet.