Problem
Part 4 of 4 Points: 0 of 1 Save Determine the area under the standard normal curve that lies to the left of (a) $Z=-0.22$, (b) $Z=-0.67$, (c) $Z=-0.38$, and $(d) Z=-0.96$. (a) The area to the left of $Z=-0.22$ is 0.4129 . (Round to four decimal places as needed.) (b) The area to the left of $Z=-0.67$ is 0.2514 . (Round to four decimal places as needed.) (c) The area to the left of $Z=-0.38$ is 0.3520 . (Round to four decimal places as needed.) (d) The area to the left of $Z=-0.96$ is $\square$. (Round to four decimal places as needect) Incorrect: 0
Solution
Step 1 ：The problem is asking for the area under the standard normal curve that lies to the left of \(Z=-0.96\). This is equivalent to finding the cumulative distribution function (CDF) at \(Z=-0.96\) for a standard normal distribution. The standard normal distribution has a mean of 0 and a standard deviation of 1.
Step 2 ：By calculating, we find that the area is approximately 0.16852760746683781.
Step 3 ：Final Answer: The area to the left of \(Z=-0.96\) is \(\boxed{0.1685}\).
