Find a possible formula for the general $n^{\text {th }}$ term of the sequence that begins as follows. Please simplify your solution. \[ 4,16,64,256,1024, \ldots \]

Step 1 ：The given sequence appears to be a geometric sequence, where each term is multiplied by a constant to get the next term.

Step 2 ：To find the general nth term of a geometric sequence, we can use the formula: \(a_n = a_1 * r^{(n-1)}\) where: \(a_n\) is the nth term of the sequence, \(a_1\) is the first term of the sequence, \(r\) is the common ratio (the constant that each term is multiplied by to get the next term), and \(n\) is the term number.

Step 3 ：From the given sequence, we can see that the first term \(a_1\) is 4, and the common ratio \(r\) is 4 (since each term is 4 times the previous term).

Step 4 ：So, we can substitute these values into the formula to find the general nth term of the sequence.

Step 5 ：\(\boxed{a_n = 4 * 4^{(n-1)}}\) is the general nth term of the sequence.