Step 1 :Define the variable x.
Step 2 :Define the equation \(\log _{6}(x+1)-\log _{6}(x-3)=2\).
Step 3 :Solve the equation to get \(x = \frac{109}{35}\).
Step 4 :Check if the solution is valid. The solution is valid if \(x > 3\).
Step 5 :The solution \(x = \frac{109}{35}\) is valid because it is greater than 3, which makes the arguments of the logarithms in the original equation positive.
Step 6 :Final Answer: The solution to the equation is \(\boxed{\frac{109}{35}}\).