Recall that the pure minor third has ratio $6 / 5$. Find the following convergent in the continued fraction expansion of $\log _{2}(6 / 5)$ : \[ \log _{2}(6 / 5) \approx[0 ; \square, \square, \square= \] : (write you answer as a fraction of whole numbers in lowest terms) In this case, our scale has notes per octave and the minor third in this scale is spanned by notes.

Step 1 ：The problem is asking for the continued fraction expansion of \( \log _{2}(6 / 5) \). Continued fractions are a way of representing real numbers as the limit of a sequence of fractions. They can provide better approximations to real numbers than ordinary (finite) fractions.

Step 2 ：To find the continued fraction expansion of a number, we can use the following steps: 1. Write down the integer part of the number (this is the first number in the expansion). 2. Subtract the integer part from the number to get a fractional part. 3. Take the reciprocal of the fractional part to get a new number. 4. Repeat steps 1-3 with the new number.

Step 3 ：Applying these steps to \( \log _{2}(6 / 5) \), we get the first term in the continued fraction expansion as 0.

Step 4 ：Subtracting the integer part from the number to get a fractional part, we get 0.2630344058337938.

Step 5 ：Taking the reciprocal of the fractional part to get a new number, we get 3.800659808434463.

Step 6 ：Repeating the steps with the new number, we get the next terms in the continued fraction expansion as 3 and 1.

Step 7 ：Final Answer: The first three terms in the continued fraction expansion of \( \log _{2}(6 / 5) \) are \(\boxed{0, 3, 1}\).