Step 1 :The question is asking for the probability that a male's growth plates fuse before the age of 17. This is a problem of normal distribution. The mean is 19.1 years and the standard deviation is 15.1 months (or 1.2583 years).
Step 2 :We need to calculate the z-score for the age of 17 and then find the corresponding probability from the standard normal distribution table. The z-score is calculated as \( (X - \mu) / \sigma \), where X is the value we are interested in, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
Step 3 :Substituting the given values into the z-score formula, we get \( z = (17 - 19.1) / 1.2583 = -1.6688741721854317 \).
Step 4 :After calculating the z-score, we can use a standard normal distribution table to find the corresponding probability. The probability that corresponds to the z-score of -1.67 is approximately 0.0476.
Step 5 :This is the area under the standard normal curve to the left of the z-score -1.67.
Step 6 :Final Answer: The probability a male's growth plates fuse before age 17 is approximately \(\boxed{0.0476}\).