Use substitution to determine the solution of the system of equations. Write the solution as an ordered pair. \[ \begin{array}{l} x+2 y=14 \\ y=3 x-14 \end{array} \] \[ \text { solution }=( \]

Step 1 ：The system of equations is given as: \(x + 2y = 14\) and \(y = 3x - 14\).

Step 2 ：We can solve this system by substitution. The second equation is already solved for \(y\), so we can substitute \(3x - 14\) for \(y\) in the first equation. This will give us an equation with only one variable, \(x\), which we can solve.

Step 3 ：After substituting \(3x - 14\) for \(y\) in the first equation, we get \(x + 2(3x - 14) = 14\).

Step 4 ：Solving this equation gives us \(x = 6\).

Step 5 ：After finding the value of \(x\), we can substitute it back into the second equation to find the value of \(y\). Substituting \(x = 6\) into \(y = 3x - 14\) gives us \(y = 4\).

Step 6 ：The solution to the system of equations is \(\boxed{(6, 4)}\).