Use the formula $P(B \mid A)=\frac{n(A \text { and } B)}{n(A)}$ to find the probability $P($ seven|not a face card) when a single card is drawn from a standard 52-card deck. $P($ seven $\mid$ not a face card $)=\square($ Simplify your answer. Type an integer or a fraction. $)$

Step 1 ：A standard deck of 52 cards contains 4 sevens and 12 face cards (the Jacks, Queens, and Kings of each suit). Therefore, there are 52 - 12 = 40 cards that are not face cards.

Step 2 ：The event A in this case is drawing a card that is not a face card, and the event B is drawing a seven. We are looking for the probability of B given A, or P(B|A).

Step 3 ：According to the formula, this is equal to the number of outcomes where both A and B occur divided by the number of outcomes where A occurs.

Step 4 ：Both A and B occur when a seven that is not a face card is drawn. Since sevens are not face cards, there are 4 such outcomes.

Step 5 ：A occurs when any card that is not a face card is drawn, which is 40 outcomes.

Step 6 ：Therefore, the probability we are looking for is \(\frac{4}{40}\) or \(\frac{1}{10}\).

Step 7 ：Final Answer: The probability P(seven|not a face card) is \(\boxed{\frac{1}{10}}\).