Determine whether the given ordered pair is a solution of the system of equations. \[ \begin{aligned} (2,6) ;-3 x+y & =0 \\ 2 x+y & =-2 \end{aligned} \]

Step 1 ：Define the ordered pair (2,6) as (x,y).

Step 2 ：Substitute (x,y) into the first equation -3x + y = 0, we get -3*2 + 6 = 0, which is true.

Step 3 ：Substitute (x,y) into the second equation 2x + y = -2, we get 2*2 + 6 = -2, which is false.

Step 4 ：Since the ordered pair (2,6) satisfies the first equation but does not satisfy the second equation, it is not a solution to the system of equations.

Step 5 ：Final Answer: The ordered pair (2,6) is \(\boxed{not}\) a solution to the system of equations.