Problem

Find (a) the range and (b) the standard deviation of the set of data. \[ 44,62,38,47,44,59,56 \] (a) The range is 24 . (Simplify your answer.) (b) The standard deviation is (Round to the nearest hundredth as needed.)

Solution

Step 1 :Given the data set \(44, 62, 38, 47, 44, 59, 56\)

Step 2 :To find the range of a set of data, we subtract the smallest number from the largest number. In this case, the smallest number is 38 and the largest number is 62. So, the range is \(62 - 38 = 24\)

Step 3 :To find the standard deviation, we first need to find the mean (average) of the data. The mean of the data is \(50.0\)

Step 4 :Then, for each number in the data, we subtract the mean and square the result. The squared differences are \(36.0, 144.0, 144.0, 9.0, 36.0, 81.0, 36.0\)

Step 5 :Next, we find the mean of these squared differences. The mean of the squared differences is \(69.42857142857143\)

Step 6 :Finally, we take the square root of this mean. This gives us the standard deviation, which is \(8.332380897952964\)

Step 7 :Rounding to the nearest hundredth, the standard deviation is \(8.33\)

Step 8 :Final Answer: (a) The range of the set of data is \(\boxed{24}\). (b) The standard deviation of the set of data is \(\boxed{8.33}\)

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