Step 1 :The problem gives us a quadratic equation in the form of \(ax^2 + bx + c = 0\). We can solve this equation using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). In this case, a = -5, b = -3, and c = 64. We will substitute these values into the quadratic formula to find the value of 't'.
Step 2 :Substituting the values into the quadratic formula, we get two solutions for 't': 3.29 and -3.89. However, time cannot be negative, so we discard the negative solution.
Step 3 :The ball hits the ground 3.29 seconds after it is thrown.
Step 4 :Final Answer: \(\boxed{3.29}\) seconds.