Step 1 :The problem is asking for the probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 97 words per minute. This is a problem of normal distribution. We know that the mean reading speed is 91 wpm and the standard deviation is 10 wpm.
Step 2 :We can use the z-score formula to calculate the z-score, which is \((X - μ) / (σ / √n)\), where X is the sample mean, μ is the population mean, σ is the standard deviation, and n is the sample size.
Step 3 :Substituting the given values into the formula, we get \(z = (97 - 91) / (10 / √10) = 1.8973665961010278\).
Step 4 :We can then use the z-score to find the probability from the standard normal distribution table. The probability corresponding to this z-score is 0.028889785561798553.
Step 5 :The probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 97 words per minute is approximately 0.0289. This means that if we randomly select 10 students, there is a 2.89% chance that their average reading speed will be more than 97 wpm.
Step 6 :Final Answer: The probability is approximately \(\boxed{0.0289}\). If 100 different samples of \(n=10\) students were chosen from this population, we would expect approximately 2.89 samples to have a sample mean reading rate of more than 97 words per minute.