Step 1 :Set up two equations based on the information given in the problem. The first equation comes from the total number of boxes: \(x + y = 26\)
Step 2 :The second equation comes from the total weight of the boxes: \(30x + 60y = 1200\)
Step 3 :Simplify the second equation by dividing everything by 10: \(3x + 6y = 120\)
Step 4 :Further simplify it by dividing everything by 3: \(x + 2y = 40\)
Step 5 :Now we have two equations: \(x + y = 26\) and \(x + 2y = 40\)
Step 6 :To graphically solve this system of equations, plot these two lines on a graph and find their intersection point.
Step 7 :The first line (\(x + y = 26\)) will intersect the y-axis at \(y = 26\) (when \(x = 0\)) and the x-axis at \(x = 26\) (when \(y = 0\)).
Step 8 :The second line (\(x + 2y = 40\)) will intersect the y-axis at \(y = 20\) (when \(x = 0\)) and the x-axis at \(x = 40\) (when \(y = 0\)).
Step 9 :By plotting these two lines on a graph, we can see that they intersect at the point (14, 12).
Step 10 :Therefore, the solution to the system of equations is \(x = 14\) and \(y = 12\).
Step 11 :This means that the paper company shipped 14 small boxes and 12 large boxes.
Step 12 :To check our solution, we can substitute these values back into the original equations: \(14 + 12 = 26\) (which is true) and \(30*14 + 60*12 = 1200\) (which is also true).
Step 13 :Therefore, our solution is correct. The final answer is \(\boxed{x = 14, y = 12}\)