Problem
(a) Write the equation in exponential form. (b) Solve the equation from part (a). (c) Verify that the solution checks in the original equation. \[ \log _{3}(3 x-3)=2 \] Part: $\mathbf{0} / \mathbf{3}$ Part 1 of 3 (a) The equation in exponential form is $\square$.
Solution
Step 1 ：Write the equation in exponential form: \(3^2 = 3x - 3\)
Step 2 ：Solve the equation from part (a): \(3x = 3^2 + 3\)
Step 3 ：Verify that the solution checks in the original equation: \(\log _{3}(3 \cdot (3^2 + 3)/3)=2\)
