Problem

Find the distance between the point (3, 4) and the line 2x - 3y = 6 using the distance formula.

Solution

Step 1 :\(Step 1: \) Write the equation of the line in slope-intercept form (y = mx + b).

Step 2 :\[2x - 3y = 6 \rightarrow y = \frac{2}{3}x - 2\]

Step 3 :\(Step 2: \) Use the distance formula to calculate the distance between the point and the line.

Step 4 :\[d = \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}}\]

Step 5 :\(Where, \) (x_1, y_1) is the point (3, 4), and A, B, and C are the coefficients from the line equation.

Step 6 :\[A = 2, B = -3, C = 6\]

Step 7 :\(Substitute \) A, B, C, x_1, and y_1 into the distance formula.

Step 8 :\[d = \frac{|2*3 - 3*4 + 6|}{\sqrt{2^2 + (-3)^2}} = \frac{|6 - 12 + 6|}{\sqrt{4 + 9}} = \frac{0}{\sqrt{13}} = 0\]

From Solvely APP
Source: https://solvelyapp.com/problems/Ww396IabSX/

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