Simplify. \[ 3 \sqrt{32}+\sqrt{98} \]

Step 1 ：Identify the prime factors of 32: \(32 = 2^5\)

Step 2 ：Apply the square root of the factors: \(\sqrt{32} = \sqrt{2^5} = 2^2\sqrt{2} = 4\sqrt{2}\)

Step 3 ：Multiply the 3 with the simplified square root: \(3\sqrt{32} = 3(4\sqrt{2}) = 12\sqrt{2}\)

Step 4 ：Identify the prime factors of 98: \(98 = 2 \times 7^2\)

Step 5 ：Apply the square root of the factors: \(\sqrt{98} = \sqrt{2 \times 7^2} = 7\sqrt{2}\)

Step 6 ：Add the two simplified expressions: \(3\sqrt{32} + \sqrt{98} = 12\sqrt{2} + 7\sqrt{2} = \boxed{19\sqrt{2}}\)