Find possible values of $a$ and $b$ that make the statement true. \[ \begin{array}{r} \int_{-3}^{3} f(x) d x+\int_{3}^{8} f(x) d x-\int_{a}^{b} f(x) d x=\int_{-1}^{8} f(x) d x \\ (a, b)=(\square) \end{array} \]

Step 1 ：The integral of a function from a to b is the area under the curve of the function from a to b. The integral from -3 to 3 plus the integral from 3 to 8 is the area under the curve from -3 to 8. The integral from -1 to 8 is the area under the curve from -1 to 8. The difference between these two areas is the area under the curve from -3 to -1. Therefore, the integral from a to b must be the integral from -3 to -1. So, a = -3 and b = -1.

Step 2 ：Final Answer: The possible values of a and b that make the statement true are \(\boxed{(-3, -1)}\).