Step 1 :The function $f(x)$ is a polynomial of degree 4, so it has 4 zeros in the complex plane.
Step 2 :The zeros of a polynomial with real coefficients always come in conjugate pairs. Therefore, the number of nonreal complex zeros must be even.
Step 3 :We know that there is 1 positive zero.
Step 4 :There must be 1 negative zero to balance out the positive zero.
Step 5 :The remaining 2 zeros must be nonreal complex zeros.
Step 6 :Final Answer: The function $f(x)$ has \(\boxed{1}\) negative zero and \(\boxed{2}\) nonreal complex zeros.