Factor completely \[ 6 x^{2}+3 x-18 \]

Step 1 ：The given expression is a quadratic equation: \(6x^{2}+3x-18\).

Step 2 ：To factorize it completely, we need to find two numbers such that their sum is equal to the coefficient of x (which is 3 in this case) and their product is equal to the product of the coefficient of \(x^{2}\) (which is 6 in this case) and the constant term (which is -18 in this case).

Step 3 ：The completely factored form of the given expression is \(\boxed{3*(x + 2)*(2*x - 3)}\).