A building contractor is to dig a foundation 45 feet long, 25 feet wide, and 9 feet deep. The contractor pays 14$ per load for trucks to remove the dirt. Each truckload holds 5 cubic yards. What is the cost to the contractor to have all the dirt hauled away?

Step 1 ：Convert the dimensions from feet to yards. Since 1 yard = 3 feet, the length is \(\frac{45}{3} = 15.0\) yards, the width is \(\frac{25}{3} = 8.33\) yards, and the depth is \(\frac{9}{3} = 3.0\) yards.

Step 2 ：Calculate the volume of the dirt to be removed. The volume of a rectangular prism can be calculated by multiplying its length, width, and height. So, the volume is \(15.0 \times 8.33 \times 3.0 = 375.0\) cubic yards.

Step 3 ：Calculate the number of truckloads needed by dividing the total volume by the volume per truckload. Since each truckload holds 5 cubic yards, the number of truckloads is \(\frac{375.0}{5} = 75\). However, since the number of truckloads should be an integer, we round up to 76 because even if a truck is not completely full, it still counts as a truckload.

Step 4 ：Calculate the total cost by multiplying the number of truckloads by the cost per truckload. Since the contractor pays $14 per load, the total cost is \(76 \times 14 = 1064\) dollars.

Step 5 ：\(\boxed{\text{The cost to the contractor to have all the dirt hauled away is \$1064.}}\)