The length of a rectangle is $8 \mathrm{~m}$ less than three times the width, and the area of the rectangle is $35 \mathrm{~m}^{2}$. Find the dimensions of the rectangle. \[ \begin{array}{l} \text { Length : } \square \mathrm{m} \\ \text { Width : } \square \mathrm{m} \end{array} \]

Step 1 ：The problem is asking for the length and width of a rectangle given that the length is 8m less than three times the width and the area is 35 square meters. We can set up two equations based on these conditions and solve for the two variables, length and width. The first equation is based on the relationship between the length and the width, and the second equation is based on the formula for the area of a rectangle (length times width).

Step 2 ：We can solve these equations simultaneously to find the values of the length and width.

Step 3 ：The solution gives two possible sets of values for the length and width: (-15, -7/3) and (7, 5). However, the dimensions of a rectangle cannot be negative, so we discard the first set of values.

Step 4 ：Therefore, the length of the rectangle is 7m and the width is 5m.

Step 5 ：Final Answer: \n\[\begin{array}{l}\text { Length : } \boxed{7} \mathrm{~m} \\text { Width : } \boxed{5} \mathrm{~m}\end{array}\]