For the quadratic function $f(x)=5-x^{2}$, find (a) the vertex, (b) the line of symmetry, and (c) the maximum or the minimum value. Then (d) graph the function. (a) The vertex is $\square$ (Type an ordered pair.) (b) The line of symmetry is $\square$. (Type an equation.) (c) Find the maximum or minimum function value Select the correct choice below and fill in the answer box to complete your choice. (Simplify your answer.) A. The maximum value is B. The minimum value is

Step 1 ：The given function is a quadratic function in the form \(f(x) = a - x^2\) where a is a constant. The standard form of a quadratic function is \(f(x) = a(x-h)^2 + k\) where (h, k) is the vertex of the parabola.

Step 2 ：To find the vertex of the parabola, we need to convert the given function into the standard form. In this case, the function is already in the standard form with h = 0 and k = 5. So, the vertex of the parabola is \(\boxed{(0, 5)}\).

Step 3 ：The line of symmetry for a parabola is always the x-coordinate of the vertex. So, the line of symmetry is \(\boxed{x = 0}\).

Step 4 ：Since the coefficient of \(x^2\) is negative, the parabola opens downwards. This means that the vertex is the highest point on the graph, so the maximum value of the function is the y-coordinate of the vertex, which is \(\boxed{5}\).

Step 5 ：To graph the function, we can plot the vertex and a few other points and then draw a smooth curve through these points. The graph will be a downward-opening parabola with the vertex at (0, 5) and the line of symmetry at x = 0.