Question 4 Determine any critical values for the function $f(x)=\frac{x^{3}}{6}-8 x$. If $f$ has multiple critical values, separate your answers with a comma. Enter just the value(s), and do not include any spaces in your answer.

Step 1 ：First, find the derivative of the function \(f(x)=\frac{x^{3}}{6}-8 x\).

Step 2 ：Then, set the derivative equal to zero and solve for x. This will give us the critical points of the function.

Step 3 ：The derivative of the function \(f(x)=\frac{x^{3}}{6}-8 x\) is \(f'(x)=\frac{x^{2}}{2}-8\).

Step 4 ：Setting the derivative equal to zero gives the equation \(\frac{x^{2}}{2}-8=0\).

Step 5 ：Solving this equation gives the critical points \(x = -4\) and \(x = 4\).

Step 6 ：These are the points at which the derivative of the function is zero.

Step 7 ：Final Answer: The critical values of the function are \(\boxed{-4, 4}\).