Find a polynomial function $\mathrm{P}(\mathrm{x})$ of degree 3 with real coefficients that satisfies the given conditions. Do not use a calculator Zeros of $-3,1$, and $0 ; P(-1)=-1$

Step 1 ：The zeros of the polynomial are the roots of the equation P(x) = 0. So, if the zeros are -3, 1, and 0, then the polynomial can be written in the form P(x) = a(x + 3)(x - 1)x, where a is a constant.

Step 2 ：We can find the value of a by substituting x = -1 into the equation and setting it equal to -1, as given in the problem.

Step 3 ：Substituting x = -1 into the equation gives P = -x*(x - 1)*(x + 3)/4

Step 4 ：Solving for a gives a_value = -1/4

Step 5 ：Substituting a = -1/4 back into the equation gives P = -x*(x - 1)*(x + 3)/4

Step 6 ：The polynomial function that satisfies the given conditions is \(\boxed{P(x) = -\frac{1}{4}x(x - 1)(x + 3)}\)