Find the perimeter of a rectangle with length $17.51 \mathrm{ft}$ and width $12.62 \mathrm{ft}$. Answer How to enter your answer (opens in new window)

Step 1 ：Given that the length is 17.51 ft and the width is 12.62 ft.

Step 2 ：The formula for the perimeter of a rectangle is \(2 \times (\text{length} + \text{width})\).

Step 3 ：Substitute the given values into the formula: \(2 \times (17.51 \text{ ft} + 12.62 \text{ ft})\).

Step 4 ：Calculate the sum inside the parentheses: \(2 \times 30.13 \text{ ft}\).

Step 5 ：\(\boxed{60.26 \text{ ft}}\) is the perimeter of the rectangle.