Hans needs to invest to help with his child's college fund. How much would he have to invest to have $\$ 98,700$ after 13 years, assuming an interest rate of $2.14 \%$ compounded dally? Do not round any intermediate computations, and round your final answer to the nearest dollar. If necessary, refer to the list of financial formulas. Assume there are 365 days in each year. s]

Step 1 ：Given that the amount of money accumulated after n years, including interest (A) is $98,700, the annual interest rate (r) is 2.14% or 0.0214 in decimal, the number of times that interest is compounded per year (n) is 365, and the time the money is invested for in years (t) is 13.

Step 2 ：We need to find the principal amount (P). So, we rearrange the formula for compound interest to solve for P: \(P = \frac{A}{(1 + \frac{r}{n})^{nt}}\)

Step 3 ：Substitute the given values into the formula: \(P = \frac{$98,700}{(1 + \frac{0.0214}{365})^{365*13}}\)

Step 4 ：Simplify the expression inside the parentheses: \(P = \frac{$98,700}{(1 + 0.00005863013698630137)^{4745}}\)

Step 5 ：Calculate the value of the expression inside the parentheses: \(P = \frac{$98,700}{1.308677927}\)

Step 6 ：Finally, calculate the value of P: \(P = $75,388.68\)

Step 7 ：So, Hans would need to invest approximately \(\boxed{$75,389}\) to have $98,700 after 13 years, assuming an interest rate of 2.14% compounded daily.