Solve the system by the addition method. \[ \left\{\begin{array}{l} x^{2}-4 y^{2}=-32 \\ 2 x^{2}+y^{2}=17 \end{array}\right. \] The solution set is (Simplify your answer. Type an ordered pair. Use a comma to separate answers as needed.)

Step 1 ：\(2*(x^{2}-4y^{2}) = 2*(-32)\)

Step 2 ：\(2x^{2}-8y^{2}=-64\)

Step 3 ：\(2x^{2}-8y^{2} - (2x^{2}+y^{2}) = -64 - 17\)

Step 4 ：\(-9y^{2} = -81\)

Step 5 ：\(y^{2} = 9\)

Step 6 ：\(y = 3\) or \(y = -3\)

Step 7 ：\(2x^{2} + 3^{2} = 17\)

Step 8 ：\(2x^{2} + 9 = 17\)

Step 9 ：\(2x^{2} = 8\)

Step 10 ：\(x^{2} = 4\)

Step 11 ：\(x = 2\) or \(x = -2\)

Step 12 ：\(2x^{2} + (-3)^{2} = 17\)

Step 13 ：\(2x^{2} + 9 = 17\)

Step 14 ：\(2x^{2} = 8\)

Step 15 ：\(x^{2} = 4\)

Step 16 ：\(x = 2\) or \(x = -2\)

Step 17 ：\(\boxed{(2, 3), (2, -3), (-2, 3), (-2, -3)}\)