Problem

A population numbers 16,800 organisms initially and grows by 8.76 each year. Suppose $P$ represents population, and $t$ the number of years of growth. An exponential function to inged the population can be written in the form $P(t)=P_{0} \cdot b^{t}$. Give the function below.

Solution

Step 1 :Given that the initial population, $P_0$, is 16,800 organisms and the growth rate, $b$, is 8.76% per year, we can express this growth rate as a decimal, so 8.76% becomes 0.0876.

Step 2 :Since the population is growing, the base of the exponent, $b$, should be 1 plus the growth rate, or 1.0876.

Step 3 :Therefore, the function that models the population growth is $P(t) = 16800 \cdot (1.0876)^t$.

Step 4 :So, the final answer is \(\boxed{P(t) = 16800 \cdot (1.0876)^t}\).

From Solvely APP
Source: https://solvelyapp.com/problems/TFwe1Mgqrr/

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