Step 1 :Calculate the total population by adding the population of each school: \(210 + 165 + 160 + 175 + 190 = 900\).
Step 2 :Calculate the standard divisor by dividing the total population by the total number of computers to be distributed: \(\frac{900}{50} = 18\).
Step 3 :Calculate the initial quotas by dividing the population of each school by the standard divisor and rounding down to the nearest whole number: \([\frac{210}{18}, \frac{165}{18}, \frac{160}{18}, \frac{175}{18}, \frac{190}{18}] = [14, 9, 8, 9, 10]\).
Step 4 :Sum up the initial quotas to get the initial apportionment: \(14 + 9 + 8 + 9 + 10 = 47\).
Step 5 :Calculate the remaining computers to be distributed by subtracting the initial apportionment from the total number of computers: \(50 - 47 = 3\).
Step 6 :Distribute the remaining computers one at a time to the schools with the largest fractional parts of their quotas. The final apportionment of computers according to Jefferson's method is \([14, 9, 9, 10, 11]\).
Step 7 :\(\boxed{\text{Final Answer: School a gets 14 computers, school b gets 9 computers, school c gets 9 computers, school d gets 10 computers, and school e gets 11 computers.}}\)