Use the one-to-one property of logarithms to solve. \[ \begin{array}{l} \ln (80-6 x)=\ln (-7 x) \\ x=\square \end{array} \]

Step 1 ：Use the one-to-one property of logarithms to solve the equation \(\ln (80-6 x)=\ln (-7 x)\).

Step 2 ：The one-to-one property of logarithms states that if \(\ln a = \ln b\), then \(a = b\). Therefore, we can set the arguments of the logarithms equal to each other and solve for \(x\).

Step 3 ：Setting \(80 - 6x\) equal to \(-7x\), we get the equation \(80 - 6x = -7x\).

Step 4 ：Solving this equation, we find that \(x = -80\).

Step 5 ：Final Answer: \(x = \boxed{-80}\)