Find all the zeros of $f(x)$. \[ f(x)=2 x^{3}+7 x^{2}-28 x+12 \] Arrange your answers from smallest to largest. If there is a double root, list it twice. \[ x=[?], \frac{[]}{[]},[] \] Enter the number that belongs in the green box.

Step 1 ：Let's find all the zeros of the function \(f(x)=2 x^{3}+7 x^{2}-28 x+12\).

Step 2 ：First, we find the roots of the equation by using the coefficients of the polynomial.

Step 3 ：The coefficients of the polynomial are [2, 7, -28, 12].

Step 4 ：By solving the equation, we find the roots to be [-6.000000000000002, 0.49999999999999983, 2.0].

Step 5 ：We then sort the roots in ascending order to get [-6.000000000000002, 0.49999999999999983, 2.0].

Step 6 ：The roots of the equation are -6, 0.5, and 2. There are no double roots.

Step 7 ：The number in the green box would be the denominator of the fractional root, which is 0.5. Since 0.5 can be expressed as 1/2, the number in the green box is 2.

Step 8 ：Final Answer: \(\boxed{2}\).