In a sample of 150 people from town A, 45\% planned to vote for the proposition. In a sample of 200 people from town B, $67 \%$ planned to vote for the proposition. Test the claim ( $2 \%$ significance level) that the percent is the same. Use town A as population 1. Select the conclusion. You should make sure you can 1) Write both the null and alternate hypotheses. 2) Know if the test is a 1 sided of 2 sided test. 3) Find the critical value. 4) Find the p-value 5) Make a conclusion. State conclusion in context of the problem. You are likely to be asked to do all these steps on the unit exam. Reject the null hypothesis. Fail to reject the null hypothesis.

Step 1 ：Define the sample sizes and the number of successes for each town: \(n1 = 150\), \(n2 = 200\), \(x1 = 67.5\), \(x2 = 134.0\).

Step 2 ：Calculate the pooled proportion: \(pooled\_p = 0.5757142857142857\).

Step 3 ：Calculate the standard error: \(se = 0.0533833842528339\).

Step 4 ：Calculate the z-score: \(z = -4.121132503665149\).

Step 5 ：Calculate the p-value: \(p\_value = 3.7701449761229355e-05\).

Step 6 ：Since the p-value is much less than the significance level of 0.02, we reject the null hypothesis. This means that we have strong evidence to suggest that the proportion of people who planned to vote for the proposition is not the same in both towns.

Step 7 ：Final Answer: \(\boxed{\text{Reject the null hypothesis.}}\)