Find the common ratio and write out the first four terms of the geometric sequence $(1.09)^{n-1}$ Common ratio is \[ \begin{array}{l} a_{1}= \\ a_{2}= \\ a_{3}= \\ a_{4}= \end{array} \] Question Help: Video Message instructor Submit Question

Step 1 ：Define the common ratio as \(r = 1.09\)

Step 2 ：Calculate the first term as \(a_{1} = r^{1-1} = 1.0\)

Step 3 ：Calculate the second term as \(a_{2} = r^{2-1} = 1.09\)

Step 4 ：Calculate the third term as \(a_{3} = r^{3-1} = 1.1881\)

Step 5 ：Calculate the fourth term as \(a_{4} = r^{4-1} = 1.29503\)

Step 6 ：\(\boxed{\text{The common ratio is } 1.09 \text{ and the first four terms of the geometric sequence are } 1.0, 1.09, 1.1881, \text{ and } 1.29503}\)