Find the focus, directrix, focal diameter, vertex and axis of symmetry for the parabola \[ 43.6 x=y^{2} \] Focus Directrix Focal diameter = Vertex Axis of symmetry

Step 1 ：The given equation is in the form of \(y^2 = 4ax\), where \(4a = 43.6\).

Step 2 ：Calculate the value of \(a\), \(a = \frac{43.6}{4} = 10.9\).

Step 3 ：The focus of the parabola is at \((a, 0)\), so the focus is at \((10.9, 0)\).

Step 4 ：The directrix of the parabola is \(x = -a\), so the directrix is \(x = -10.9\).

Step 5 ：The focal diameter of the parabola is \(4a\), so the focal diameter is \(43.6\).

Step 6 ：The vertex of the parabola is at the origin \((0, 0)\).

Step 7 ：The axis of symmetry of the parabola is the y-axis \(x = 0\).

Step 8 ：\(\boxed{\text{Final Answer: The focus of the parabola is at }(10.9, 0), \text{ the directrix is } x = -10.9, \text{ the focal diameter is } 43.6, \text{ the vertex is at the origin } (0, 0), \text{ and the axis of symmetry is the y-axis } x = 0}\).