Step 1 :First, we need to find the area that lies between \(Z=-2.14\) and \(Z=2.14\). The area to the left of \(Z=2.14\) is 0.9838 and the area to the left of \(Z=-2.14\) is 0.0162. The area between these two Z-scores is the difference of these two areas, which is 0.9838 - 0.0162 = 0.9676.
Step 2 :Next, we need to find the area that lies between \(Z=-2.51\) and \(Z=0\). The area to the left of \(Z=0\) is 0.5 and the area to the left of \(Z=-2.51\) is 0.0060. The area between these two Z-scores is the difference of these two areas, which is 0.5 - 0.0060 = 0.4940.
Step 3 :Finally, we need to find the area that lies between \(Z=1.92\) and \(Z=2.06\). The area to the left of \(Z=2.06\) is 0.9803 and the area to the left of \(Z=1.92\) is 0.9726. The area between these two Z-scores is the difference of these two areas, which is 0.9803 - 0.9726 = 0.0077.
Step 4 :So, the areas under the standard normal curve that lie between the given Z-scores are approximately \(\boxed{0.9676}\), \(\boxed{0.4940}\), and \(\boxed{0.0077}\), respectively.