Problem

What is the range of the inverse function of $f(x)=$ $x^{3}$ ? $f^{-1}(x)>0$ $f^{-1}(x)<0$ $f^{-1}(x) \geq 0$ $f^{-1}(x) \leq 0$ All real numbers

Solution

Step 1 :The inverse function of \(f(x) = x^{3}\) is \(f^{-1}(x) = \sqrt[3]{x}\).

Step 2 :The cube root function, \(\sqrt[3]{x}\), is defined for all real numbers. This is because you can take the cube root of any number, positive, negative, or zero.

Step 3 :Therefore, the range of the inverse function \(f^{-1}(x) = \sqrt[3]{x}\) is all real numbers.

Step 4 :\(\boxed{\text{The range of } f^{-1}(x) = \sqrt[3]{x} \text{ is all real numbers.}}\)

From Solvely APP
Source: https://solvelyapp.com/problems/Q8loWXJB4K/

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