\[ h=164 t-16 t^{2} \] Find all values of $t$ for which the rocket's height is 92 feet.

Step 1 ：Set the height \(h\) equal to 92 to get the equation: \(92 = 164t - 16t^2\)

Step 2 ：Rearrange the terms to get: \(16t^2 - 164t + 92 = 0\)

Step 3 ：This is a quadratic equation in the form \(at^2 + bt + c = 0\). Solve it using the quadratic formula: \[t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Step 4 ：Substitute \(a = 16\), \(b = -164\), and \(c = 92\) into the quadratic formula to get: \[t = \frac{164 \pm \sqrt{(-164)^2 - 4*16*92}}{2*16}\]

Step 5 ：Calculate the expression under the square root: \((-164)^2 - 4*16*92 = 26896 - 5888 = 21008\)

Step 6 ：Substitute the result back into the equation to get: \[t = \frac{164 \pm \sqrt{21008}}{32}\]

Step 7 ：Calculate the square root: \(\sqrt{21008} \approx 144.94\)

Step 8 ：Substitute the result back into the equation to get: \[t = \frac{164 \pm 144.94}{32}\]

Step 9 ：Solve for \(t\) to get two possible solutions: \[t = \frac{164 + 144.94}{32} \approx 9.65\] and \[t = \frac{164 - 144.94}{32} \approx 0.59\]

Step 10 ：\(\boxed{t \approx 0.59, 9.65}\) are the times at which the rocket's height is 92 feet.