\begin{tabular}{|c|c|} \hline$f(x)=\mathbf{2 x}-\mathbf{1 0}$ \\ \hline$x$ & $f(x)$ \\ \hline 0 & $\square$ \\ \hline 2 & $\square$ \\ \hline 4 & $\square$ \\ \hline 6 & $\square$ \\ \hline \end{tabular}

Step 1 ：The function is given as \(f(x)=2x-10\).

Step 2 ：We are asked to find the value of the function at \(x=0\), \(x=2\), \(x=4\), and \(x=6\).

Step 3 ：We can find the value of the function at these points by substituting the values of \(x\) into the function.

Step 4 ：When \(x=0\), \(f(x)=2*0-10=-10\).

Step 5 ：When \(x=2\), \(f(x)=2*2-10=-6\).

Step 6 ：When \(x=4\), \(f(x)=2*4-10=-2\).

Step 7 ：When \(x=6\), \(f(x)=2*6-10=2\).

Step 8 ：So, the completed table is: \begin{tabular}{|c|c|} \hline \(f(x)=2x-10\) \\ \hline \(x\) & \(f(x)\) \\ \hline 0 & -10 \\ \hline 2 & -6 \\ \hline 4 & -2 \\ \hline 6 & 2 \\ \hline \end{tabular}

Step 9 ：\(\boxed{\text{The values of the function } f(x) \text{ at } x=0, x=2, x=4, \text{ and } x=6 \text{ are } -10, -6, -2, \text{ and } 2 \text{ respectively.}}\)