A certain electronics manufacturer found that the marginal cost $C$ to produce $\times \mathrm{DVD} /$ Blu- ray players can be found using the equation $C=0.03 x^{2}-6 x+800$. If the marginal cost were $\$ 2626$, how many DVD/Blu-ray players were produced? Select an answer

Step 1 ：The problem is asking for the number of DVD/Blu-ray players produced when the marginal cost is $2626. This can be solved by setting the equation \(C=0.03 x^{2}-6 x+800\) equal to $2626 and solving for \(x\).

Step 2 ：Solving the equation gives two solutions: -166.207938774685 and 366.207938774685.

Step 3 ：However, the number of DVD/Blu-ray players produced cannot be negative. Therefore, the valid solution is 366.207938774685.

Step 4 ：Rounding to the nearest whole number, the number of DVD/Blu-ray players produced when the marginal cost is $2626 is approximately \(\boxed{366}\).