Find the zeros and their multiplicities for the function \( f(x) = 2x^3 - 3x^2 - 11x + 6 \).

Step 1 ：Step 1: Let's set the function equal to zero and solve for x. That is, solve \( 2x^3 - 3x^2 - 11x + 6 = 0 \).

Step 2 ：Step 2: Notice that the cubic polynomial can be factored as \( (x-1)(2x+1)(x-3) = 0 \).

Step 3 ：Step 3: Setting each factor equal to zero gives the zeros x = 1, x = -1/2, and x = 3.

Step 4 ：Step 4: Since each zero appears only once in the factored form of the polynomial, each zero has multiplicity 1.